Problem with pie charts

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asunix
Posts: 4
Joined: 22 January 2016, 12:56

Problem with pie charts

Post by asunix »

I am trying to set up a pie chart that has two accounts and only items in state blocked,
if I try I can not see anything displayed.
The following picture describes the situation:
https://www.dropbox.com/s/oemo7rglnnk2w ... 6.png?dl=0
If I select only one account all work fine:
https://www.dropbox.com/s/e6ns58e0hunpt ... 4.png?dl=0
Can I configure a rule to filter two accounts in a pie charts with only items in state blocked ?
Thank you
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Angeman
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Posts: 2301
Joined: 28 December 2008, 21:28
Location: Toulouse, France
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Re: Problem with pie charts

Post by Angeman »

That's because you have 2 "The account is XXX" conditions in an "All" group. As a transaction cannot belong to 2 accounts it's always false. So you need to create a "One of the following is true" group and add the 2 "The account is XXX" conditions in it.
asunix
Posts: 4
Joined: 22 January 2016, 12:56

Re: Problem with pie charts

Post by asunix »

Hi Angeman thank for the quick reply. I knew the answer.
There is a problem with the translation of certain words in Italian.
In Italian the "Conditions" have the following "modifiers"
None (Nessuno)
All (Tutti)
None (Nessuno)
https://www.dropbox.com/s/ctwsx3d2aydbh ... 4.PNG?dl=0
Changing the language to English see:
https://www.dropbox.com/s/qybamaxjioapf ... 3.PNG?dl=0
None
All
Any
"Any" in Italian should be "Qualsiasi" and not "Nessuno".

Translation is present in both versions of iCompta iOs and OSX.
On the iCompta Guide there isn't any reference to setup "Conditions" for Reports.
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Angeman
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Re: Problem with pie charts

Post by Angeman »

Thanks, I'll fix the localization bug.
zh_olga
Posts: 76
Joined: 19 November 2013, 21:48

Re: Problem with pie charts

Post by zh_olga »

you don't have "one of the following", you only have "all" "any" and "none"

"One of the following" = "any" ?
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Angeman
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Re: Problem with pie charts

Post by Angeman »

zh_olga wrote: 14 November 2021, 08:58 "One of the following" = "any" ?
Yes
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